Write an equation in slope intercept form of the line that passes through the given point and is paraell to the graph of the equation. 1) (4,2) x=-3 2) (2,-1) y=-3/2+6 3) (2,-2) y=-x-2

1.) x = -3...this is a vertical line with an undefined slope. A parallel line to a vertical line is also a vertical line. A vertical line is represented by x = a numberthat number being the x coordinate of ur point(4,2).
so ur parallel line is : x = 4 <==

2.) y = -3/2x + 6slope here is -3/2. A parallel line will have the same slope.

y = mx + b
slope(m) = -3/2
(2,-1)...x = 2 and y = -1
now we sub into the formula and find b, the y int
-1 = -3/2(2) + b
-1 = -3 + b
-1 + 3 = b
2 = b
so ur parallel line is : y = -3/2x + 2 <==

y = -x - 2the slope here is -1. A parallel line will have the same slope

y = mx + b
slope(m) = -1
(2,-2)...x = 2 and y = -2
now we sub into the formula and find b, the y int
-2 = -1(2) + b
-2 = -2 + b
-2 + 2 = b
0 = b
so ur parallel equation is : y = -x + 0 which can be written as : y = -x <=

Here, feel free to ask if there are any questions