3x + 2y = 7 x - y + 3 = 0 what is the resulting equation? 3x - y - 3 + 2y = 7 3(y - 3) + 2y = 7 3y - 3 + 2y = 7

I'm not comfortable with having two " = " signs in the same equation, at least not in this situation.

You apparently meant to type in the system of linear equations

3x + 2y = 7
 x  -   y  = -3

but did not separate 3x + 2y = 7 and  x  -   y  = -3 with a comma as required.

I will assume that you meant to share:

3x + 2y = 7
 x  -   y  = -3              This system of linear equations has a solution, but there 
                                 will be no "resulting equation."

Please ensure that you have copied down this problem exactly as it was originally presented.  Explain what we are to do with

3x + 2y = 7 x - y + 3 = 0:     How do we interpret this?

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12