Agolfer hits a golf ball with a velocity of 36.0 meters/second at an angle of28.0°. if the hang time of the golf ball is 3.44 seconds, what is the range ofthe golf ball? 83 meters 87 meters 108 meters 94 meters

108 meters.

Step-by-step explanation:

A golfer hits a golf ball with a velocity of 36 meter per second of an angle of 28°.

If the ball hangs for 3.44 seconds then we have to find the range.

When a golf ball is hit by the golfer then golf ball follows a parabolic path.

Vertical component of the velocity lifts the ball up in the air and horizontal component moves it in horizontal direction.

Since we have to find the horizontal distance covered by the ball we will consider the horizontal component = ( v cos θ )

= 36 cos 28° = 31.78 meter/second

Now velocity =

so 31.78 =

S = 3.44 × 31.78 = 109 meter.

Therefore, nearest answer will be 108 meters.

it would be 3 ÷by 6 because the number on each side

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.