Me the vertices of a square are a(-2 4), b(4,4), c(4,-2), d(-2,-2). the diagonals of the square intersect at their midpoints. what are the coordinates of the midpoint where the diagonals intersect

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

the function makes a strait line horizontally with no x intercept but a y intercept at 9.