What are the solutions of the equation x^4 - 5x^2 - 14 = 0? use factoring to solve a) x = +-√7 and x = +-√2 b) x = +-i√7 and x = +-i√2 c) x = +-i√7 and x = +-√2 d) x = +-√7 and x = +-i√2

D) x = +-√7 and x = +-i√2

Step-by-step explanation:

Given:

x^4 -5x^2 -14 = 0

This can be written as

x^4 + 2x^2 - 7x^2 -14 = 0

x^2(x^2 + 2) -7(x^2 + 2) = 0

(x^2 +2)(x^2 - 7) = 0

x^2 + 2 = 0   and x^2 - 7 = 0

x^2 = -2

x =

x = ±i√2

x^2 - 7 = 0

x^2 = 7

x = ±√7

Therefore, solutions are D) x = +-√7 and x = +-i√2

Hope this will helpful.

Thank you.

right

step-by-step explanation:

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.