In standard position point (2, 3) is on the terminal side of angle θ. find the values of sine, cosine, and tangent of θ? show all work.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: