Acar dealership sells 20 cars when there is a $2,000 markup over the factory price of each vehicle. the sales department determines that for each $400 decrease in markup an additional 6 cars are sold. write a function that models the total monthly profit p(n). let n represent the number of markdowns. a) p(n) = 2400n2 + 4000n + 40,000 b) p(n) = 2400n2 − 4000n + 40,000 c) p(n) = −2400n2 + 4000n + 40,000 d) p(n) = −2400n2 − 4000n + 40,000

C)  

Step-by-step explanation:

Since, profit = number of car sold × total markup

Original markup = $2,000

Also, the original number of sold cars = 20,

Let the markup is decreases by n times of $400,

New markup = ( 2000 - 400n ) dollars,

According to the question,

For each $400 decrease in markup an additional 6 cars are sold.

So, new number of sold cars = 20 + 6x,

Hence, the total monthly profit P(n) would be,

P(n) = ( 2000 - 400n )( 20 + 6n )

Option 'C' is correct.

d

step-by-step explanation:

1. 523.33 cubic inches

2. 113.04 cubic inches.

3. 17.41.

4. 16.49

i think this should be your answer

hope i

-lavira : )