An intitial population of 745 quail increases at an annual rate of 16%. write an exponential function to model the quail population. what will the approximate population be after 4 years?

Based on the initial population of the quails and the rate at which they are increasing, the exponential function would be 745 x ( 1 + 16%) ^ n and the population after 4 years would be 1,348 quails.

The population of quail at any period of time is:

= Initial population x ( 1 + rate of increase) ^ number of years

Assuming number of years is n, the function would be:

= 745 x ( 1 + 16%) ^ n

If n is 4 years, the population would be:

= 745 x ( 1 + 16%)⁴

= 1,348 quails

In conclusion, the population would be 1,348 quails.

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you already gave the answer

step-by-step explanation:

an = 22 + (n-1) *6

110 seats

step-by-step explanation:

an=a1+(n-1)(d)

a1 = 22   this is the first item in the sequence

d =6   this is how the sequence goes up

a)   an = 22 + (n-1) *6

b) a12 = 22 + (12-1) *6

    a12 = 22+11*6

  a12 = 22 +88

  a12 = 110