Find two consecutive even integers such that the sum of the smaller and five times the larger is 202

Let's define our two even integers as "x" and "x+2", as they have to be consecutive. Next, let's convert these words into math. First, we know it has to be the sum of the smaller, or x, and five times the larger. So, we have x+ 5(x+2). Then, we know it equals 202, so we have x + 5x+ 10 = 202. We can clean up the left side by combining like terms and making it 6x+10 = 202. Next, we subtract 10 from both sides, getting us 6x = 192. We then divide both sides by 6, getting us 32. Therefore, the integers are 32 and 34. Hope this helped!

i think there was a typo. you wrote pat brings 3 quarts of ice-cream to the party. each serving of ice-cream is 1 6 quart. how many total servings of ice-cream does pat bring to the party? i think the bold is supposed to be 1/6. so 1 quart of ice cream = 6 servings. 6 * 3 = 18.

the answer is 18.