Can you me solve 4^(2x+1)=3^(x-2) for x? you!

In order to solve the equation we should take  the natural logarithm of both sides of the equation (the goal is to remove the variable from the exponent)ln(4^(2x+1))=ln(3^(x−2))
(2x+1)ln(4)=(x-2)ln(3)
2x*ln(4)+ln(4)=xln(3)-2ln(3)
2x*ln(4)-xln(3)=-ln(4)-2ln(3)
x(2ln(4)-ln(3))=-ln(4)-2ln(3)
x=-ln(4)-2ln(3)/(2ln(4)-ln(3))

Idon’t know but hope this you