Maribel goes to a coin star to turn in her change. the coins are quarters and dimes. the machine gives her 14.80 credit for 76 coins. how many quarters and dimes does she have?

10*d+25*q=1480, where d is the number of dimes and q is the number of quarters.If she has 76 coins total, then: 76=q+d Solving for d yields d=76-q, which we substitute into the first equation: 10*(76-q)+25*q=1480 Simplifying and solving for q: 760-10*q+25*q=1480 15*q=720 q=48 Substituting back into the second equation: d=76-48=28 Check solution: 10*28+25*48=1480 Maribel had 28 dimes and 48 quarters.

Neither of them have sex