If the angle θ in the two-source interference equations is small, then using small-angle approximations yields the equation ym=r(m+1/2)λd, where r is the distance from the sources to the points where they are being detected (in young's experiment the screen, in this example the road), and ym is the distance from the central maximum to the minimum of order m. use this equation to find the distance from the central maximum to the minimum in the previous part

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: