Aparticle moves with velocity function v(t) = 2t2 - 3t - 3, with v measured in feet per second and t measured in seconds. find the acceleration of the particle at time t = 2 seconds. (4 points) a. 3/4 ft/s^2 b. -1 ft/s^2 c. 32ft/s^2 d. 5 ft/s^2

d. 5 ft/s^2

Step-by-step explanation:

The acceleration is the derivative of the velocity.

In this problem, we have the velocity function

So the acceleration function is:

.

Find the acceleration of the particle at time t = 2 seconds

This is a(2). So:

.

The correct answer is

d. 5 ft/s^2

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!