The volume of a sphere is v = 4⇡r3. the surface area of 23 a sphere is a = 4⇡r . find the rate at which the volume is changing when the surface area is 100 cm2 and the surface area is increasing at a rate of 4cm2/sec (leave your answer in an exact form – do not write your answer as a rounded decimal). show your work!

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92