Meh pls what is the equation, in point-slope form, for a line that goes through (8, −4) and has a slope of −56 ? y+4=−56(x+8)y−4=−56(x+8)y−4=−56(x−8 )y+4=−56(x−8)

The answer should be A because point slope form is y-y1=m(x-x1)M is the starting point and its -56 and y1(-4) is the y value of the coordinate point and x1(8) is the x value of the coordinate point. it changes to y+4 because two negative signs make a positive(y--4)