In triangle abc, a = 18.2, ∠b = 62°, and ∠c = 48°. find b

To find angle a we do 180-(62+48)=180-110=70
angle a =70
with this we can use the sin rule
a/sin(A)=b/sin(B)=c/sin(C)
since we have side a and angle A  and angle b we can do:
18.2/sin(70)=b/sin(62)
then we can times by sin(62)
(18.2/sin(70))*sin(62)=17.1