In a group of 25 students, 12 students play basketball, 11 students play football. five students play both sports. a student is chosen randomly from this group. what is the probability that the student plays both basketball or football?

P(student plays both basketball or football)=18/25

Step-by-step explanation:

We are given that:

In a group of 25 students, 12 students play basketball, 11 students play football. Five students play both sports.

Now, A student is chosen randomly from this group.

What is the probability that the student plays both basketball or football?

Probability of any event=no. of favorable outcomes/total no. of outcomes

  Here, no. of favorable outcomes

=no. of students who plays both basketball or football

=  12+11-5

= 18

and, total no. of outcomes=25

Hence, P(student plays both basketball or football)=18/25

expression #3 is not equivalent. the others are.