Which set of ordered pairs represents a function? {(2, –2), (1, 5), (–2, 2), (1, –3), (8, –1)} {(3, –1), (7, 1), (–6, –1), (9, 1), (2, –1)} {(6, 8), (5, 2), (–2, –5), (1, –3), (–2, 9)} {(–3, 1), (6, 3), (–3, 2), (–3, –3), (1, –1)}

So I'm going to assume that each of the groups of ordered pairs have 5 ordered pairs each. And, to make it easier for myself, I'll list it down here :

(1) [(2, -2), (1, 5), (-2,2), (1, -3), (8, -1)]
(2) [(3, -1), (7, 1), (-6, -1), (9, 1), (2, -1)]
(3) [(6, 8), (5, 2), (-2, -5), (1, -3), (-2, 9)]
(4) [(-3,1), (6, 3), (-3, 2), (-3, -3), (1, -1)

The hint to finding which of the groups of ordered pairs is not a function, is to look for the group that has the same input in more than one ordered pair. So, in this case, when we look at them, we'll find that (1), (3), (4) aren't functions, because in (1) they repeat 1 more than once, in (3), they repeat -2 more than once, and in (4), they repeat -3 thrice, I believe.

I believe the only one left is (2), which is the second group or ordered pairs, because it's the only one that does not repeat any inputs.

YOUR ANSWER IS : (2), which is [(3, -1), (7, 1), (-6, -1), (9, 1), (2, -1)]

Set square i think so