![\bf \textit{we know the range for }cos\left( \frac{1}{x} \right)\textit{ is }[-1,1]\textit{ therefore} \\\\\\ -1~\ \textless \ ~cos\left( \frac{1}{x} \right)~\ \textless \ ~1\impliedby \textit{multiplying all sides by }x^2 \\\\\\ -1x^2~\ \textless \ ~x^2cos\left( \frac{1}{x} \right)~\ \textless \ ~1x^2\implies -x^2~\ \textless \ ~x^2cos\left( \frac{1}{x} \right)~\ \textless \ ~x^2](/tpl/images/0273/1877/23b0e.png)
Could some explain the sandwich theorem (calculus/ limits)
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Mathematics, 29.09.2019 07:20 teacherpreacher
Could some explain the sandwich theorem (calculus/ limits)
Answers: 1
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