Where is (0,19) located? quadrant i quadrant ii quadrant iii quadrant iv x-axis y-axis

Let P(a, b) be a point on the coordinate plane. Then the following hold:

i) If a>0, b>0 then P is in the I.Quadrant.

ii) If a<0, b>0 then P is in the II.Quadrant.

iii) If a<0, b<0 then P is in the III.Quadrant.

iv) If a>0, b<0 then P is in the IV.Quadrant.

v) If a=0 and b is positive or negative, then P is on the y-axis.

vi) If b=0 and a is positive or negative, then P is on the x-axis.

Since we have: a=0, and 19 positive, then this point is on the y-axis.

y-axis

Idon’t know actually i’m in 5th grade and don’t know

A. p = 2(l + w)p/2 - l = ww = p/2 - l b. while isolating the variable w in the equation, i first divided both sides by 2 and then i subtracted l from both sides. i hope this .