An object moves according to the law s = t2 + 5t - 8. what is the average rate of change of s with respect to t in the interval t to (t + △ t)?

 The average rate of change can be calculated as:

Mavg = (((t+∆t)² + 5(t+∆t) - 8) - (t² + 5t - 8)) / ∆t  = (∆t² + 2t∆t + 5∆t) / ∆t
= ∆t + 2t + 5 

So, the average rate of change is: ∆t + 2t + 5

the answer is (-4,-4)

hope this ! : d

there still no table