The vertex of the function’s graph is given. find c. y = -3x2 + 6x + c; (1, 0)

Vertex form of a parabola is:
y = a(x - h)^2 + k

Where vertex (h,k) is given to be (1,0) and x terms are factorable by "a" = -3
y = -3(x-1)^2 + 0

expand the parenthesis
y = -3(x-1)(x-1)
y = -3(x^2 - x - x + 1)
multiply -3 through parenthesis
y = -3x^2 + 6x - 3
Compare to given equation
c = -3

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