Alan has two more than twice as many chocolates as does alice, and half as many chocolates as does nadia. if alice has ‘a' number of chocolates, then in terms of ‘a', how many chocolates do alan, alice and nadia have

Alan has two more than twice as many chocolates as does alice
Alan = 2Alice + 2 (1)

Alan has half as many chocolates as does nadia
Alan = 1/2 Nadia
so Nadia = 2Alan (2)

if Alice has 'a' number of chocolates
from (1)
Alan = 2a + 2 (3)
from (2) and (3)
Nadia = 2 (2a+2) = 4a+4 (4)

So Alan Alice and Nadia have
(2a+2) + a + (4a+4) = 7a+ 6 #