Which recursive formula can be used generate the sequence shown where f(1)=5 and n> 1?
5,-1,-7,-13,-
a) f(n+1)=(n)+6
b) f(n)=f(n+1)-6
c) f(n+1)=f(n)-6
d) f(n+1)= -6f(n)

So we notice that the difference between the nubmers is 6 (5-6=-1, -1-6=-7, etc)

so therefor it must be something with -6, and n>1 so
f(n)=-6n

the difference to the next erm is 6 so the answe ris C
f(n+1)=f(n)-6

C