*! * (guaranteed brainliest for correct answer! ) which equation has no solution? a. 13y+2-2y=10y+3-y b. 9(3y+7)-2=3(-9+9) c. 32.1y+3.1+2.4y-8.2=34.5y-5.1 d. 5(2.2y+3.4)=5(y-2)+6y

In this sort of situation, an equation has no solution if the variables cancel each other out and it has a non-zero solution, and so we can do this by inspection, looking for the ys on the LHS to cancel those on the RHS.

A has 13 on one side and 9 on the other so will have a solution
B only has a positive y on one side so will have a solution
C - the variables cancel so we will have to do it properly:

This means that whilst the variables cancel, it comes to a valid solution (0=0) which means this has infinite solutions for y. Since you can stick any value of y in and it will always return 0=0

D - Again the variables cancel:

This is an invalid equation as 0 obviously does not equal 27. Therefore, this equation has no solutions, meaning this is the correct answer.

1. 0.3 •4 is the same as 4 groups of 0.32. 7•0.8 is the same as 7 groups of 0.83. it increases by 0.5 every time, so 0.5x4 it increases by 0.9 every time, so 0.9x5. 0.9•12=10.86. 0.47•5=2.35i can finish the next ones in a separate post