Given: ∆akl, ak = 9 m∠k = 90° m∠a = 60° the area of ∆akl

The question asks us to find the area of a triangle. First, before we do anything, we need to state the formula for the area of a triangle, which is , where is the base and is the height. In this scenario, we are given the length of the height, which is . We need to find the length of KL, which is the base. We can see that this triangle is a 30, 60, 90 degree triangle, meaning that it has some special properties. First off, it means that the hypotenuse is two times the side opposite to it, which in this case is that AL (the hypotenuse) is two times the length of AK, which is the side opposite to it. Thus, the length of the hypotenuse is . Now, we can use the Pythagorean Theorem to find the length of the base. 






Now that we found all the required values for the formula, just plug it in and solve. When we do so, we get that the area is . Hope this helped!

2(10 - 13x) + 9x = -34x + 6020 - 26x + 9x = -34x + distributive property-17x = -34x + subtraction property (subtracted 20 from both sides)17x = addition property (added 34x to both sides)x = 40/ division property (divided both sides by 17)