![\bf \begin{cases} f(x)=-x-2\\ g(x)=x^2\\ (g\circ f)(-6)\implies g[~~f(-6)~~] \end{cases} \\\\\\ \textit{now, what is f(-6)?}\qquad f(-6)=-\stackrel{x}{(-6)}-2\implies f(-6)=6-2 \\\\\\ \boxed{f(-6)=4} \\\\\\ g[~~f(-6)~~]\implies g[~~4~~]=(4)^2](/tpl/images/0235/9700/e09b8.png)
Functions, i appear to be confused upon this particular question
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Mathematics, 17.09.2019 09:00 zoet1027
Functions, i appear to be confused upon this particular question
Answers: 2
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