One root of f(x)=x3+10x2-25x-250=-10. what are all the roots of the function? use the remainder theorem. x = –25 or x = 10 x = –25, x = 1, or x = 10 x = –10 or x = 5 x = –10, x = –5, or x = 5

option d is correct x = –10, x = –5, or x = 5    

step-by-step explanation:

given : function -

one root x=-10

the remainder theorem : solve the polynomial through long division.

using formula   p(x) = (x – a) q(x)   +   r(x).

where, p(x) is the dividend , (x-a) is the divisor or root , q(x) is the quotient , r(x) is the remainder

now we solve the given function using remainder theorem

,

when remainder is zero our quotient =

i.e,

solve  

therefore, roots of function is -10,5 or-5

hence, option d is correct x = –10, x = –5, or x = 5

its a trick question

step-by-step explanation:

dogs love water, just turn on the hose and it will run in circles chasing the water all day : )

the answer is 40.

proof: