Hannah has $482.75 in her savings account. she would like her account balance to be more than $1,250 before she buys a cell phone. hannah plans to save $85.25 a month. how many months will it be until she can buy a cell phone? (hint: write and solve an inequality that represents this situation.) *

The inequality equation would be 482.75+82.25x1250 subtracting the amount that Hannah already has from the goal would amount to 767.25, therefore she only needs to save up to equal or more than this amount. Dividing this by 82.25 would then give us how many months this would take equal or greater than 9.33 months.

idk man good luck man

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)