F. if a 2 x 6 (which means the actual dimensions of the board are 1.5 in. x 5.5 in.) milled from the same wood (and therefore has the same density) weighs 3.2 lb, how long is the board?

By definition, we have to

 W = V * Dw

 W: weight

 V: Volume

 D: Density

 Clearing and Substituting we have:

 V = W / Dw = (3.2 lb) / (0.021 (lb / in ^ 3)) = 152.38 in ^ 3

 Then, on the other hand, the volume is

 V = l * w * d

 l: long

 w: width

 d: depth

 Clearing and substituting

 l = V / (w * d) = (152.38 in ^ 3) / ((1.5 in) * (5.5 in)) = 18.5 in

 The answer is 18.5 in

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

answer: ur v dumb

step-by-step explanation: