Side wx of rectangle wxyz lies on the line y= 2/3 x + 1. if point z is located at (-6,4), what is the equation on the line on which side wz lies? a y = -3/2x b y=2/3x+8 c y=-3/2x-5 d y=2/3x-26/3

1) Side WZ is perpendicular to side WX

2) The product of the slopes of two perpedicular lines is - 1

3) The line where the side WZ lies is y  = (2/3)x + 1

4) The slope of a line with formula y = mx + b is m, therefore the slope of y = (2/3)x + 1 is 2/3, and the slope of the line where the side WZ lies is - 1 / (2/3) = - 3/2

5) The equation of a line with slope m that passes through the point (a,b) is:

y - b = m (x - a)

Then the equation of our line is y - (4) = (- 3/2) (x - (-6)

=> y - 4 = - (3/2)x - 9

=> y = -(3/2)x - 9 + 4

=> y = (-3/2)x - 5

option C. y = (-3/2)x - 5

If jon had $4.00 then takes away $2.25, then he should have $1.75 left. $4.00 - $2.25 = $1.75 hope this ; )