The length of a rectangle is twice its width. if the area of the rectangle is 128 ft2 , find its perimeter.

Length(l)= 2w
Width(w)= w
Area(A) = l*w

A= 128 ft²
128= l*w
128= (2w)w
2w²= 128
w²= 64
w=√64= 8 ft
w= 8 ft

length(l)= 2w
l=2(8)
l=16 ft

P= 2l+2w
P=2(16)+2(8)= 32+16= 48ft
P= 48ft

The Perimeter of this rectangle is 48 feet.

Leave any questions you still have in the comments below please! Thank you! Hope this helped! :)

You're gonna need to post the table