Given: δавс, m∠acb = 90° cd ⊥ ab , m∠acd = 60° bc = 6 cm find cd, area of δabc

CD = 3√3 cm

Area  ΔABC =18cm²

Step-by-step explanation:

the angle  < ACB =90°

<ACD =60° therefore <BCD =30°

cos 30°= x/6

x= 3√3 cm

Area  ΔABC =1/2×base×height

the  ΔABC is a 45 45 90 triangle

: AC =6√3 cm

ΔABC = 1/2×6√3×6

ΔABC =18√3 cm²

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2