Mathematics, 02.08.2019 14:20 esmeralda1209
Simplify the given expression, using only positive exponents. then complete the statements that follow. [ (x2y3)−1 (x−2y2z)2 ] 2 , x ≠ 0, y ≠ 0, z ≠ 0.
Answers: 2
![[ (x^2*y^3)^{-1}*(x^{-2}*y^2*z)^2]^2 = \frac{z^4*y^2}{x^{12}}](/tpl/images/0162/0415/fb4fc.png)
![[ (x^2*y^3)^{-1}*(x^{-2}*y^2*z)^2]^2](/tpl/images/0162/0415/cfa8a.png)
![[ (x^{-1*2}*y^{-1*3})*(x^{-2*2}*y^{2*2}*z^2)]^2 \\\[ (x^{-2}*y^{-3})*(x^{-4}*y^{4}*z^2)]^2](/tpl/images/0162/0415/45a1f.png)
![[ (x^{-2}*y^{-3})*(x^{-4}*y^{4}*z^2)]^2\\ \\[ (x^{-2}*x^{-4})*(y^{-3}*y^{4})*z^2]^2](/tpl/images/0162/0415/f01d8.png)
![[ (x^{-2}*x^{-4})*(y^{-3}*y^{4})*z^2]^2\\\[ (x^{-2-4})*(y^{-3+4})*z^2]^2 \\\[ (x^{-6})*(y)*z^2]^2](/tpl/images/0162/0415/8c839.png)
![[ (x^{-6})*(y)*z^2]^2 \\[ (x^{-6*2})*(y^2)*z^{2*2}] \\[ (x^{-12})*(y^2)*z^{4}] \\\ $\frac{y^2*z^4}{x^{12}}](/tpl/images/0162/0415/7e131.png)
![[(x^{2}y^{3})^{-1}.(x^{-2}y^{2}z)^{2}]^{2}](/tpl/images/0162/0415/e268a.png)
![[x^{-2}.y^{-3}.x^{-4}.y^{4}.z^{2}]^{2}](/tpl/images/0162/0415/9ad10.png)
![[x^{-2-4}.y^{-3+4}.z^{2}]^{2}=[x^{-6}.y^{1}.z^{2}]^{2}=x^{(-6-6)}.y^{1+1}.z^{2+2}=x^{-12}y^{2}z^{4}](/tpl/images/0162/0415/c6b7e.png)
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Simplify the given expression, using only positive exponents. then complete the statements that foll...
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