If a quadratic equation with real coefficients has a discriminant of 3 then the two roots must be

In a quadratic equation

q(x) = ax^2 + bx + c 

The discriminant is = b^2 - 4ac

We have that discriminant = 3

If b^2 - 4ac > 0, then the roots are real.

If b^2 - 4ac < 0 then the roots are imaginary

In this problem b^2 - 4ac > 0   3 > 0

then the two roots must be real

what shape is

i think it would be c

mark brainliest if im right

step-by-step explanation: