⦁determine if the equation represents a direct variation. 8x = 1.6y ⦁ suppose y varies directly with x. write a direction variation equation that relates x and y. then find the value of y when x = 12. y=5 when x=2. ⦁ for the data in the table, does y vary directly with x? if it does, write an equation for the direct variation. x y -6 9 1 -1.5 8 -12 ⦁ for the data in the table, does y vary directly with x? if it does, write an equation for the direct variation. x y -2 1 3 6 8 11

Part A:

Given that 



Thus, x = ky where k = 2.

Therefore, the given equation is a direct variation.

Part B:

If y varies directly as x, then y = kx.

Given that y = 5 when x = 2, then



When x = 12, y = 2.5(12) = 30.

Part C:

If y varies directly as x, then y = kx.

Given that y = 9 when x = -6, then



It can be seen that the equation above satisfies all the rows of the given table, therefore, y varies with x for the data in the question and the equation for the direct variation is

Part 4:

If y varies directly as x, then y = kx.

Given that y = 1 when x = -2, then



It can be seen that the equation above does not satisfies the other rows of the given table, therefore, y does not vary with x for the data in the question.