Given the system of linear equations. -x + y = 5, 4x + y = 10 part a: use substitution to find the solution to the systems of equations. include all of your work in your final answer. part b: algebraically verify your answer to part a. include all of your work in your final answer.

You can solve for y in equation one, then substitute that answer into equation two. -x+y=5add x to both sides to solve for y. the x's cancel each other out on the left side of the equation. y=5+xnow substitute that answer in the second equation. 4x+y=104x+(5+x)=105x+5=10subtract 5 from both sides5x=5divide both sides by 5 to solve for xx=1substitute that answer in equation one to now solve for y. -x+y=5-1+y=5add one to both sides y=6use those answers to check if they work in the given equations. -1+6=5 yes4(1)+6=10 yes

A: 18/15b : 7 - -8 = 15 , 12 - -6 = 18 the y variable always goes over the x variables, c : same thing a