Two triangles can be formed with the given information. use the law of sines to solve the triangles. b = 29°, b = 26, c = 28

According to law of sines, sinB/b=sinC/c. sin29 degrees=0.485, so we can solve for sinC in the equation, and sinC=0.522. Angle C=arcsin(0.522), there are two possibilities for C.
case 1:C=31.5 degrees approximately by a calculator. Angle A=180-29-31.5=119.5 degrees. We can solve for the length of a by using law of sines again. sinA/a=sinB/b, a=46.7
case 2: C=148.5. Angle A=180-29-148.5=2.5 degrees. SinA/a=sinB/b, a=2.34. 

Think of it as five or above give it a shove. change the 5 or above to the right to a zero and add one to the number on the left.