The area of a rectangular is (x^3-5x^2+3x-15), and the width of the rectangular is (x^2+3). if area = length x width, what is the length of the rectangle?

Option D. (x -5)

Step-by-step explanation:

Area of the rectangle is given as A = (x³ - 5x² + 3x - 15)

The width of the rectangle is W = (x² + 3)

Then we have to find the length (L) of the rectangle.

We know that area A = L× W

By putting the values of L and A

(x³- 5x² + 3x -15) = L× (x² + 3)

Now we factorize the numerator first

(x³-5x²+3x-15) = x²(x - 5) + 3(x - 5) = (x² + 3)(x - 5)

Now

Therefore Option D (x - 5) is the answer.

then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

the lateral surface area of a sphere is 2πrh where h=2r.

then:

surface area = 4πr^2.

in this case, r=8 units ⇒ surface area = 4π(8 units)^2. = 256π sq. units!

then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

is their an equation anywhere i can take a   look at it and see if i am right.