Assume the probability of a boy being born is the same as the probability of a girl being born. find the probability that a family with five children will have the given composition. the two oldest children are girls.

For independent events, the probability of A and B is P(A) * P(B), so since the sex of the first child has no bearing on the sex of the second and since the future children have no bearing either, assming a 50% chance of having a girl either time, the probability of having a girl the first two children is 50% * 50%, or 25%

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm