Chenoa starts with $250 in her savings account. each month she adds $15. which recursive function rule models the total amount in chenoa’s savings account at the end of each month? a)an=250⋅an−1 and a1=15 b)an=15⋅an−1 and a1=250 c)an=15+an−1 and a1=250 d)an=250+an−1 and a1=15

Chenoa starts with $250 in her saving account and each month she adds $15 in her saving account.

Therefore, we obtain a sequence as:

250, (250+15), (250+15+15),...

250, 265, 280,....

So, we get the first term () as 250.

Now , we can clearly observe that the first term is 250 and second term is obtained by adding 15 to the first term that is 265 and so on.

Similarly in an arithmetic progression, last term is and its previous term is .

Similarly, will be obtained by adding 15 to its previous term .

So, and =250.

Therefore, Option C is correct.

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )