What is the equation, in standard form, of a parabola that contains the following points? ( -2, -23.5)(0,-4.5)(4,-26.5)

The equation of parabola is .

Step-by-step explanation:

Equation of a parabola is quadratic equation.

Let the equation of parabola be

                 .... (1)

The parabola contains points ( -2, -23.5), (0,-4.5), (4,-26.5).

Put (0,-4.5) in equation (1),

Put this value in equation (1).

              ... (2)

Put  ( -2, -23.5) and  (4,-26.5) in equation (2).

                    .... (3)

                 .... (4)

On solving (3) and (4), we get

and

Therefore the value of parabola is

$12. that is my answer.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°