Aregular hexagon is dilated by a scale factor of 75 to create a new hexagon. how does the perimeter of the new hexagon compare with the original perimeter?

Let the length of the original hexagon be x:
the perimeter of the hexagon will be:
P=length*number of sides
P=6*x=6x
After the dilation the new length became:
length=scale factor × original length
=75 × x
=75x
thus the new perimeter will be:
6×75x
=450x
hence the new perimeter compared to the old one will be:
450x/6x
=75
the new perimeter is 75 times the old one

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm