Drag and drop an answer to each box to correctly complete the proof.

given: m∥nm∥n , m∠1=50∘m∠1=50∘ , and m∠2=42∘m∠2=42∘ .

prove: m∠5=92∘
it is given that m∥nm∥n , m∠1=50∘m∠1=50∘ , and m∠2=42∘m∠2=42∘ . by the , m∠3=88∘m∠3=88∘ . because angles formed by two parallel lines and a transversal are congruent, ∠3≅∠4∠3≅∠4 . by the angle congruence theorem, m∠3=m∠4m∠3=m∠4 . using substitution, 88∘=m∠488∘=m∠4 . angles 4 and 5 form a linear pair, so by the , m∠4+m∠5=180∘m∠4+m∠5=180∘ . substituting gives 88∘+m∠5=180∘88∘+m∠5=180∘ . finally, by the , m∠5=92∘m∠5=92∘ .

Answer these questions showing your work plz

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