Find the equation of a line that is perpendicular to the line y = x + 7 and has the same y-intercept as 3y = 2x - 9. state the answer in standard form.

The standard for is x + y = -3

Step-by-step explanation:

To start, we know that the slope of perpendicular lines are opposite and reciprocal. Since the perpendicular line has a slope of 1, we know the new line will have a slope of -1.

To find the intercept of the second equation, solve for y and look for the constant.

3y = 2x - 9

y = 2/3x - 3

This gives us an intercept of -3.

Now that we have the slope and intercept we can use slope-intercept form and plug in the information. Then we simply need to solve for the constant.

y = mx + b

y = -x - 3

x + y = -3

lol

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204