Which point-slope form passes through the point (-2,1) and has a slope of 3?
a. (y-1)=3(x+2)
b. (x+2)=3(y-1)
c. (y+1)=3(x-2)
d. (x-2)=3(y+1)

The formula for point slope form is (y-y1) = m(x - x1)

In this formula m will always be the slope. So, you can substitute 3 in for m

(y-y1) = 3(x-x1)

y1 is the y-coordinate and x1 is the x-coordinate. So, you can substitute them in and you will be done.

(y - 1) = 3(x - (-2))

But since it is minus a negative it changes to a positive so it would be:

(y -1) = 3(x + 2)

Hope this helps!

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90