Mathematics, 17.10.2019 13:10 keldrykmw4

Question is attached. answer and provide work. worth 50+ points

Answers: 2

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NUMBER 1
Elimination of x to find y
2x + 3y = 1
2x + y = -9
- (substract)
2y = 10
y = 5

Elimination of y to find x
2x + 3y = 1 (multiply 1)
2x + y = -9 (multiply 3)

2x + 3y = 1
6x + 3y = -27
- (substract)
-4x = 28
x = -7

NUMBER 2
Elimination of y to find x
10x - 2y = 24
6x + 2y = 8
+ (add)
16x = 32
x = 2

Elimination x to find y
10x - 2y = 24 (multiply 3)
6x + 2y = 8 (multiply 5)

30x - 6y = 72
30x + 10y - 40
- (substract)
-16y = 112
y = -7

NUMBER 3
Eliminate y to find x
x - 4y = 1
2x + 4y = 26
+ (add)
3x = 27
x = 9

Eliminate x to find y
x - 4y = 1 (multiply 2)
2x + 4y = 26 (multiply 1)

2x - 8y = 2
2x + 4y = 26
- (substract)
-12y = -24
y = 2

NUMBER 4
Elimination of y to find x
x + y = 6
x - y = 2
+ (add)
2x = 8
x = 4

Elimination of x to find y
x + y = 6
x - y = 2
- (substract)
2y = 4
y = 2

NUMBER 5
Elimination of q to find p
p - q = 8
2p - q = 19
- (substract)
-p = -11
p = 11

Elimination of p to find q
p - q = 8 (multiply 2)
2p - q = 19 (multiply 1)

2p - 2q = 16
2p - q = 19
- (substract)
-q = -3
q = 3

Answer from: Quest

step-by-step explanation:

Which of the following best describes the focus of a parabola?

Answer from: Quest

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

= 2×(-2)+(-8)×(6)+(-8)×(-5)

= -4-48+40

= -12

hence, v.w= -12

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