Solve the compound inequality 8x > –32 or 6x ≤ –48.

On the 8x > –32 first divide by the 8 from the both sides.

8x/8 as a fractions and it is greater than negative 32/8 as a fraction. And the equals to x is greater than negative 4.

On the 6x ≤ –48. Then divide by 6 from the both sides.

6x/6 as a fractions and it is less than  negative 48/6 as a fraction. And the equals to x≤ negative 8.

I’m tome