Can someone ? a ship moves through the water at 30 miles/hour at an angle of 30° south of east. the water is moving 5 miles/hour at an angle of 20° east of north. identify the ship's vector, the water current's vector, and the vector representing the ship's actual motion.

The first thing you should do is write each speed in vector form.
 v1: vector water velocity
 v2: vector boat speed with respect to water
 writing the vectors we have
 v1 = (5 * COS (20 * (PI () / 180)) i) + (5 * SENO (20 * (PI () / 180)) j)
 v2 = (30 * COS (30 * (PI () / 180)) i) - (30 * SENO (30 * (PI () / 180)) j)
 The vector representing the ship's current motion will be given by the sum of vectors v1 and v2
 v1 + v2 = (30.67922522 i) + (15.67922522 j)