The area of a triangle is 80x^5y^3. the height of the triangle is x^4y. what is the length of the base of the triangle?

Area of a triangle = 1/2 * base * height

Area, A = 80x^5 · y^3

Base, b = ?

Height, h = x^4 · y

Therefore, 80x^5 · y^3 = 1/2 * b * x^4 · y

Multiply the equation by 2

2 * 80x^5 · y^3 = 2 * 1/2 * b * x^4 · y

160x^5 · y^3 = b * x^4 · y

b * x^4 · y = 160x^5 · y^3

Divide the equation by x^4 · y

(b * x^4 · y)/ x^4 · y = (160x^5 · y^3) / x^4 · y

b = 160x^(5 – 4) · y^(3 – 1)

b = 160x · y^2

The length of the base of the triangle is 160x · y^2

answer: i think it is (1,-2)